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help > RE: Parameterization
Jul 21, 2013 02:07 PM | Xin Kang
RE: Parameterization
I figure out a simple solution:
theta_east = full( theta(east) );
disp(sprintf('East Center: %05d (%f, %f) pi',east,theta_east/pi,phi(east)/pi));
It works on Matlab 2013a.
theta_east = full( theta(east) );
disp(sprintf('East Center: %05d (%f, %f) pi',east,theta_east/pi,phi(east)/pi));
It works on Matlab 2013a.
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| Title | Author | Date |
|---|---|---|
| pauline maillard | Jan 27, 2012 | |
| Trina Du | Feb 3, 2012 | |
| Hugh Wang | Dec 14, 2016 | |
| Vera Gramigna | May 9, 2014 | |
| Xin Kang | Jul 21, 2013 | |
| Li Shen | Jul 21, 2013 | |
| pan hong | May 2, 2013 | |
| Li Shen | Feb 6, 2012 | |